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4.9x^2+39.2x+14=0
a = 4.9; b = 39.2; c = +14;
Δ = b2-4ac
Δ = 39.22-4·4.9·14
Δ = 1262.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39.2)-\sqrt{1262.24}}{2*4.9}=\frac{-39.2-\sqrt{1262.24}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39.2)+\sqrt{1262.24}}{2*4.9}=\frac{-39.2+\sqrt{1262.24}}{9.8} $
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